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7y^2+15y-2y^2=25+y^2
We move all terms to the left:
7y^2+15y-2y^2-(25+y^2)=0
We add all the numbers together, and all the variables
5y^2-(25+y^2)+15y=0
We get rid of parentheses
5y^2-y^2+15y-25=0
We add all the numbers together, and all the variables
4y^2+15y-25=0
a = 4; b = 15; c = -25;
Δ = b2-4ac
Δ = 152-4·4·(-25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-25}{2*4}=\frac{-40}{8} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+25}{2*4}=\frac{10}{8} =1+1/4 $
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